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Last updated on September 15, 2025
The derivative of e^(2/x) provides insight into how the function changes with respect to slight variations in x. Derivatives are crucial in various real-life applications, such as calculating rates of change and modeling exponential growth. In this article, we delve into the derivative of e^(2/x) in detail.
To understand the derivative of e^(2/x), we represent it as d/dx (e^(2/x)) or (e^(2/x))'.
Using the chain rule, the derivative is found to be -2/x² * e^(2/x). The function e^(2/x) is differentiable across its domain, and its derivative is crucial for analyzing exponential growth and decay processes. Key concepts include: -
Exponential Function: e^u, where u is a function of x.
Chain Rule: A differentiation technique used for composite functions.
Power Rule: Used for differentiating functions of the form x^n.
The derivative of e^(2/x) can be expressed as d/dx (e^(2/x)) or (e^(2/x))'.
The formula to differentiate e^(2/x) is: d/dx (e^(2/x)) = -2/x² * e^(2/x), This formula is applicable for all x ≠ 0.
We can derive the derivative of e^(2/x) using various methods. Here are some approaches:
Let's demonstrate the differentiation of e^(2/x) using the chain rule:
To prove the differentiation of e^(2/x) using the chain rule, we set: f(x) = 2/x
Then e^(2/x) becomes e^f(x).
The differentiation process involves: g(x) = e^u, where u = 2/x
Differentiating e^u gives: g'(x) = e^u * u' u' = d/dx (2/x) = -2/x²
Thus, the derivative of e^(2/x) is: d/dx (e^(2/x)) = e^(2/x) * (-2/x²) = -2/x² * e^(2/x)
Higher-order derivatives are obtained by differentiating the first derivative successively. For example, the second derivative involves differentiating the first derivative of e^(2/x) again. Higher-order derivatives are significant in understanding the behavior and curvature of functions like e^(2/x).
For the first derivative, we write f′(x), which gives the rate of change of the function. The second derivative, f′′(x), is derived from the first derivative and provides insights into the concavity of the function.
The nth Derivative, denoted as fⁿ(x), describes the change in the rate of change and can be useful in various applications.
When x = 0, the function e^(2/x) is undefined.
Therefore, its derivative cannot be evaluated at this point. For positive or negative values of x where x ≠ 0, the derivative of e^(2/x) is -2/x² * e^(2/x).
Students often make errors when differentiating e^(2/x). Understanding the correct process is key to avoiding these mistakes. Here are some common errors and solutions:
Calculate the derivative of e^(2/x) * x²
Let f(x) = e^(2/x) * x².
Using the product rule, f'(x) = u'v + uv' Here, u = e^(2/x) and v = x².
Differentiate each term: u' = -2/x² * e^(2/x) v' = 2x
Substitute these into the equation: f'(x) = (-2/x² * e^(2/x)) * x² + (e^(2/x)) * 2x
Simplify the terms: f'(x) = -2e^(2/x) + 2xe^(2/x)
Thus, the derivative is -2e^(2/x) + 2xe^(2/x).
The derivative is calculated by dividing the function into parts and applying the product rule. Each part is differentiated separately and then combined for the final result.
A bacteria culture grows at a rate modeled by y = e^(2/x), where y is the population size and x is the time in hours. Find the rate of growth at x = 2 hours.
Given y = e^(2/x), Differentiate y with respect to x: dy/dx = -2/x² * e^(2/x)
Substitute x = 2 into the derivative: dy/dx = -2/(2²) * e^(2/2) = -2/4 * e = -1/2 * e
The rate of growth at x = 2 hours is -1/2 * e.
By substituting x = 2 into the derivative, we determine the rate of growth of the bacteria culture at that point in time.
Find the second derivative of y = e^(2/x).
First, find the first derivative: dy/dx = -2/x² * e^(2/x)
Now differentiate again: d²y/dx² = d/dx [-2/x² * e^(2/x)]
Using the product rule: = [-2/x² * d/dx (e^(2/x)) + e^(2/x) * d/dx (-2/x²)] = [-2/x² * (-2/x² * e^(2/x)) + e^(2/x) * (4/x³)]
Simplify: = [4/x⁴ * e^(2/x) + 4/x³ * e^(2/x)] = 4/x⁴ * e^(2/x) * (1 + x)
Thus, the second derivative is 4/x⁴ * e^(2/x) * (1 + x).
The second derivative is found by differentiating the first derivative, applying the product rule again, and simplifying the resulting expression.
Prove: d/dx (e^(4/x)) = -4/x² * e^(4/x).
Let y = e^(4/x). Using the chain rule: u = 4/x Then, y = e^u.
The derivative is: dy/dx = e^u * du/dx du/dx = -4/x²
Therefore, dy/dx = e^(4/x) * (-4/x²) dy/dx = -4/x² * e^(4/x) Hence proved.
The proof is accomplished by identifying the inner function and applying the chain rule to differentiate e^(4/x).
Solve: d/dx (x * e^(2/x))
Use the product rule: d/dx (x * e^(2/x)) = (d/dx (x) * e^(2/x) + x * d/dx (e^(2/x)))
Substitute d/dx (x) = 1 and d/dx (e^(2/x)) = -2/x² * e^(2/x): = (1 * e^(2/x) + x * (-2/x² * e^(2/x))) = e^(2/x) - 2/x * e^(2/x) = e^(2/x) * (1 - 2/x)
Therefore, the derivative is e^(2/x) * (1 - 2/x).
The function is differentiated using the product rule, simplifying the expression to achieve the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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